Xemectrum

flee0308 wrote:Jim bought some chocolates and gave half of it to Ken. Ken bought some sweets and gave half of it to Jim. Jim ate 12 sweets and Ken ate 18 chocolates. The ratio of Jim’s sweets to chocolates became 1:7 and the ratio of Ken’s sweets to chocolates became 1:4. How many sweets did Ken buy?

This question lor. Stupid, really.

i can't solve it

Let C be the number of choclates Jim had and S be the number of sweets Ken had, after they gave away half of their sweets/choclates.

7(S-12)=C
7S-84=C-(1)

4S=C-18
4S+18=C -(2)

(1)=(2),
4S+18=7S-84
102=3S
S=34
2S=68

Ken bought 68 sweets.

However, this method is "illegal" cause p6 were not taught stimultaneous equations yet. They had to use models, or use only 1 variable in algebra.

Let S be the number of sweets Ken gave away.

7(S-12)=4S+18
7S-84=4S+18
3S=102
S=34
2S=64

flee0308 wrote:Let C be the number of choclates Jim had and S be the number of sweets Ken had, after they gave away half of their sweets/choclates.

7(S-12)=C
7S-84=C-(1)

4S=C-18
4S+18=C -(2)

(1)=(2),
4S+18=7S-84
102=3S
S=34
2S=68

Ken bought 68 sweets.

However, this method is "illegal" cause p6 were not taught stimultaneous equations yet. They had to use models, or use only 1 variable in algebra.

Let S be the number of sweets Ken gave away.

7(S-12)=4S+18
7S-84=4S+18
3S=102
S=34
2S=64

it hurt my eye

Psle is so lame haha PLSE AKA PLS STOP LEARNING ENGLISH...lol haha

noeltqs wrote:Psle is so lame haha PLSE AKA PLS STOP LEARNING ENGLISH...lol haha

you more lame keep posting smileys

when u reach sec 2 or 3 u will find that its actually very easy to do lols

Susashiden wrote:when u reach sec 2 or 3 u will find that its actually very easy to do lols

sec1 didn't even learn that

Boredness wrote:

Susashiden wrote:when u reach sec 2 or 3 u will find that its actually very easy to do lols

sec1 didn't even learn that

thats y i said when reach sec 2 - 3 ...O.o

any idea when the results will be out?